Left Softkey

[DrivingMobileInnovation]

Why I can't detect if left softkey is clicked just like other keys?

[bogdan.galiceanu]

I think you can, using the keycapture module. See this thread (although rather old) for a discussion about it.

Here's an example:

import keycapture, appuifw, e32


def cb_capture(key):
	if(key==keycapture.EKeyLeftSoftkey):
		print "Left softkey pressed"
	elif(key==keycapture.EKeyRightSoftkey):
		print "Right softkey pressed"
		capturer.stop()
		app_lock.signal()

capturer=keycapture.KeyCapturer(cb_capture)
capturer.keys=([keycapture.EKeyLeftSoftkey, keycapture.EKeyRightSoftkey])

capturer.start()

app_lock=e32.Ao_lock()
app_lock.wait()

[Versoul]

There is no it intercepts pressing and in the menu though so it will turn out very much it will be not convenient. Here so I do

import appuifw,e32,graphics
body=graphics.Image.new((176,208))
def keys(x):
 if x['type']==3:
  if x['scancode']==164:
   body.text((50,80),u'button pressed',0x0000ff,font=u'Alb17b')
   canvas.blit(body)
appuifw.app.body=canvas=appuifw.Canvas(event_callback=keys)
body.clear(0xff0000)
canvas.blit(body)
e32.Ao_lock().wait()

It is the best variant but it is necessary to work with graphics

[DrivingMobileInnovation]

Thank you so much bogdan.galiceanu and Versoul. Versoul's solution is perfect for me.

[DrivingMobileInnovation]

BTW is that x['type']==3 same as x['type']==appuifw.EEventKey ?

[Versoul]

DrivingMobileInnovation: its mean x['type']==appuifw.EEventKeyDown
Without it the code of function will be called out 2 times by pressing and unpressing key

EEventKey = 1
EEventKeyUp = 2