using a configuration file

[roidayan]

hey

i want my script to write/read configuration file.
how should i save it ? as in location.
so it will know if its in memory card or on the phone
and also after i make my scripts to sis so if a user install to storage card or phone config will be created in appropriate location.

thx

[carlus1]

Read this, ...
http://discussion.forum.nokia.com/fo...d.php?t=127983

you can save your configuration in a file and read the file after that...

[roidayan]

that doesnt answer my question.
I want to know how my script can know to location to save the configuration file.
as if to somewhere in the storage card if script is in storage card or to phone memory if script is in phone memory.

[bogdan.galiceanu]

that doesnt answer my question.
I want to know how my script can know to location to save the configuration file.
as if to somewhere in the storage card if script is in storage card or to phone memory if script is in phone memory.

Are you talking about a configuration file that you create? Because if it's so, you just specify where to create/save the file in your script. If you're talking about a pre-existing file, I don't know.

[roidayan]

yes i create.
my question is how i check where to create.
i want the script to check itself if its on the memory card or the phone memory so based this it will use diff location

[aya42]

i want my script to write/read configuration file.
how should i save it ? as in location.
so it will know if its in memory card or on the phone
and also after i make my scripts to sis so if a user install to storage card or phone config will be created in appropriate location.

Best place is probably CWD, which is the directory which the active SIS is installed to. Something like this...

# Example config data
CONFIG = 'foo';

# Save it
f = open('config', 'w')
f.write(CONFIG)
f.close()

# Load it
f = open('config', 'r')
CONFIG = f.read()
f.close()

[roidayan]

ha ok thx.
if i run the script from python shell before making it sis
it will create/read the config from the same dir as the script file ?

[aya42]

if i run the script from python shell before making it sis
it will create/read the config from the same dir as the script file ?

No. It will go into the directory the PythonScriptShell was installed to - something like E:\Private\2000b1a5.

If you want to save to the directory where the currently running script is located, then try...

import sys, os

CONFIG_FILENAME = 'config.cfg'

try:
    raise Exception
catch Exception:
    filepath = sys.exc_info()[2].tb_frame.f_code.co_filename
filedir, filename = os.path.split(filepath)
configfile = os.path.join(filedir, CONFIG_FILENAME)
f = open(configfile, 'w')
# etc.

[roidayan]

seems sys.exc_info always gives me (None, None, None)
tried also os.path.dirname(sys.argv[0]) which gives the pythonshell dir i think

[aya42]

seems sys.exc_info always gives me (None, None, None)

It will only return something meaningful when called inside an 'except' block. Looks like I erroneously used the word 'catch' rather than 'except' in the code I previously posted. Try the following code verbatim...

try:
    raise Exception
except Exception:
    print sys.exc_info()

If that prints (None, None, None), then there's something seriously wrong with Python.

tried also os.path.dirname(sys.argv[0]) which gives the pythonshell dir i think

Indeed, that's why the above code uses the traceback object to find the filename of the currently running script, which, as far as I know, is the only reliable way to get it.

When packed as a SIS file, sys.argv[0] will point to the default.py script, but when run from the PythonScriptShell, it will point to the PythonScriptShell's default.py, which is not the file you want.

[JOM]

Impressive, very many thanx !!! Been looking for this for months !!! ...got close, but never thought about raising an exception by myself !!! Can't wait the evening to try it out

Cheers,

--jouni

[miohtama]

Impressive, very many thanx !!! Been looking for this for months !!! ...got close, but never thought about raising an exception by myself !!! Can't wait the evening to try it out

Cheers,

--jouni

You can do this if you import the module

import os, sys

mod = sys.modules[__name__]
file = mod.__file__
path = os.path.dirname(file)