Opening URLS in Phones Browser

[KjT]

Hello,

This seems to be the place to find some help

i have been using a script i found to hopefully allow myself to open some URLS from my own pys60 application. I thought my code was correct but its not. I connect ok to the network etc but it wont actually open the URL i give it. How cna i open a page that is supplied by me?? Hope to hear some neat responses!!

Ken

Here is the little snippet im using

def display_in_browser(url):
    """
    Launches the browser with the given url 
    """
    import e32
    import sysinfo
    internal_url = '4 '+ url + ' 1'
    b = 'BrowserNG.exe'
    e32.start_exe(b, ' "%s"' %internal_url, 4)

display_in_browser("http:\\www.rte.ie")

[JOM]

This seems to be the place to find some help

Well, you actually need Browsing help, not python, but let's see...

I connect ok to the network etc but it wont actually open the URL

Are you using S60 3.0, 3.1 or 3.2 device? There are different web browsers, so you need to know which one you try to use.

In your code you try to launch the "new" browser and your comments seem to suggest that you managed to launch it? Did you get to Bookmarks view or did you get some error note? What do you mean with "connect ok to network", if your URL wasn't launched?

In short: what did you try to do, how did you try to do it, what actually happened, what makes you think that it really happened, what did you expect to happen, any ideas about possible reasons for any of this.

Btw you did download and study the Browser (command line) API document from Forum Nokia beforehands, didn't you

Wondering,

--jouni ex-tester and ex-error manager

[unoll]

your code has an error. try:

    internal_url = '4 '+ url + ' 1'
    b = 'BrowserNG.exe'
    e32.start_exe(b, ' "%s"' %internal_url)

and it seems to be important, that the homepage you've set in you browser is your bookmarks page, otherwise (at least in my fon) nothing gets opened.

--u

Hello,
Here is the little snippet im using

def display_in_browser(url):
    """
    Launches the browser with the given url 
    """
    import e32
    import sysinfo
    internal_url = '4 '+ url + ' 1'
    b = 'BrowserNG.exe'
    e32.start_exe(b, ' "%s"' %internal_url, 4)

display_in_browser("http:\\www.rte.ie")

[gaba88]

Hi KjT welcome to the Python Discussion boards
i think you are just asking for opening a URL. then plz check the code below:

import e32

apprun = 'z:\\system\\programs\\apprun.exe'
browser = 'z:\\System\\Apps\\Browser\\Browser.app'
url = 'name of your url'
e32.start_exe(apprun, browser + ' "%s"' %url , 1)

hope this helps give a feedback