RecordControl

[mahesh_aquarius]

getting null pointer at


record = (RecordControl)player.getControl("RecordControl");

even on emulator
plz tell me how to resolve this prblm

Player player = Manager.createPlayer("capture://video");

player.addPlayerListener(this);
player.realize();

its ok till here but after this null ptr arises


record = (RecordControl)player.getControl("RecordControl");

[raj_J2ME]

Hi,
I guess Either the player of the record object must be null,
check the code

try {
// Create a Player that captures live audio.
Player p = Manager.createPlayer("capture://audio");
p.realize();
// Get the RecordControl, set the record stream,
// start the Player and record for 5 seconds.
RecordControl rc = (RecordControl)p.getControl("RecordControl");
ByteArrayOutputStream output = new ByteArrayOutputStream();
rc.setRecordStream(output);
rc.startRecord();
p.start();
Thread.currentThread().sleep(5000);
rc.commit();
p.close();
} catch (IOException ioe) {
} catch (MediaException me) {
} catch (InterruptedException ie) { }
and the link

http://discussion.forum.nokia.com/fo...ad.php?t=89162

please check the code by putting the println()'s or debug.
Thanks,

[mahesh_aquarius]

hi raj

player object is having some reference but when it is passed to record control obj rc having null

Player player = Manager.createPlayer("capture://video");

player.addPlayerListener(this);
player.realize();

//setup recording

record = (RecordControl)player.getControl("RecordControl");
record.setRecordLocation("file:///c:/videos/");
record.setRecordSizeLimit(300000);

conn = (FileConnection)Connector.open("capture://video",Connector.READ_WRITE);
if(!conn.exists()) conn.create();
stream = conn.openOutputStream();
record.setRecordStream(stream);

tell me whether this right or not

[raj_J2ME]

Hi,
I gave you that code.why dont you try with that..doing some work on it..
Thanks,

[mahesh_aquarius]

il definitely try tnks for the code,

only difference in ur code is it records audio and writes to stream whereas my code records video writes o/p to a location

thnks again il try ur code also

[raj_J2ME]

Hi,
Yeah thats true..thats the difference ..
However you can just change that and can work..right..
I hope that will help..
Thanks,

[shashankgr8]

Hi i am Using the Same Code for Nokia 3110c and nokia 5220 musicxpress its Working very Fine but once i m running it on Nokia 5880 xpress Music its not able to store the stream into file can any body help me plz its too urgent!!

Even once i m tring to record the video and trying to upload the stream to the server then also giving the same error any idea ??

[shashankgr8]

hi all this here i m facing one problem i m recording video using record control in nokia 5880 xpress music but i am not storing it any where in the file system i m uploading it to my server but the problem is the qualitiy of the video is not at all good means at some places it get stoped and resume the play from some diff. place here i m giving u my code if have any solution plz gimme


private void showCamera()
{
try {
player = Manager.createPlayer("capture://video");
player.realize();

videoControl = (VideoControl)player.getControl("VideoControl");
int width = getWidth();
int height = getHeight();

videoControl.initDisplayMode(VideoControl.USE_DIRECT_VIDEO, this);
try {
videoControl.setDisplayLocation(2, 2);
videoControl.setDisplaySize(width - 4, height - 4);
} catch (MediaException me) {}

videoControl.setVisible(true);


} catch (IOException ioe) {} catch (MediaException me) {}
}


private void RecordVideo()
{
try{
control = (RecordControl)player.getControl("RecordControl");
control.setRecordStream(Bstream);
player.start();
repaint();
control.startRecord();
}
catch (Exception e)
{
Alert alert = new Alert("Error
Record",e.getMessage),null,AlertType.ERROR);
Display.getDisplay(mid).setCurrent(alert);
}
}


private void StopVideoRecording()
{
try{
control.stopRecord();
control.commit();
//Bstream.close();
FileUploader uploader = new FileUploader(Bstream.toByteArray
(),System.currentTimeMillis()+".mp4");
player.stop();
player.deallocate();
player.close();
Bstream = null;
repaint();
}
catch (Exception e)
{
Alert alert = new Alert("Stop",e+"",null,AlertType.ERROR);
Display.getDisplay(mid).setCurrent(alert);
}
}

/**
Now this is the code for file upload
*/

public void upload(byte[] imageData, String url,int length,String Filename)
{
url+="&filename="+Filename+"&filesize="+length;
DataOutputStream oStrm = null;
ContentConnection connection = null;
try {
connection = (ContentConnection) Connector.open(url);
oStrm = connection.openDataOutputStream();
oStrm.write(imageData);
oStrm.flush();
}
catch (IOException e)
{
}
}


Thnaks and Regards
Shashank Shekhar

[jitu_goldie]

Hi,
Was u checked out that after uploading the data to server that the uploaded video is not proper.

Also u can try RecordControl.setRecordLocation(url); no need of data uploader class. can try in this way too..

private void showCamera()
{
try {
player = Manager.createPlayer("capture://video");
player.realize();

videoControl = (VideoControl)player.getControl("VideoControl");
int width = getWidth();
int height = getHeight();

videoControl.initDisplayMode(VideoControl.USE_DIRECT_VIDEO, this);
try {
videoControl.setDisplayLocation(2, 2);
videoControl.setDisplaySize(width - 4, height - 4);
} catch (MediaException me) {}

videoControl.setVisible(true);


} catch (IOException ioe) {} catch (MediaException me) {}
}


private void RecordVideo()
{
try{
control = (RecordControl)player.getControl("RecordControl");
control.setRecordLocation(URL);// eg: http://abc.com/..
player.start();
repaint();
control.startRecord();
}
catch (Exception e)
{
Alert alert = new Alert("Error
Record",e.getMessage),null,AlertType.ERROR);
Display.getDisplay(mid).setCurrent(alert);
}
}


private void StopVideoRecording()
{
try{
control.stopRecord();
control.commit();
player.stop();
player.deallocate();
player.close();

repaint();
}
catch (Exception e)
{
Alert alert = new Alert("Stop",e+"",null,AlertType.ERROR);
Display.getDisplay(mid).setCurrent(alert);
}
}

pls check and reply

thanks,
jitu_goldie..

[shashankgr8]

ya u r right .. the video is not proper ... thanks i will try your idea thanks

[arungupta_2jan]

Hi,
Was u checked out that after uploading the data to server that the uploaded video is not proper.

Also u can try RecordControl.setRecordLocation(url); no need of data uploader class. can try in this way too..

private void showCamera()
{
try {
player = Manager.createPlayer("capture://video");
player.realize();

videoControl = (VideoControl)player.getControl("VideoControl");
int width = getWidth();
int height = getHeight();

videoControl.initDisplayMode(VideoControl.USE_DIRECT_VIDEO, this);
try {
videoControl.setDisplayLocation(2, 2);
videoControl.setDisplaySize(width - 4, height - 4);
} catch (MediaException me) {}

videoControl.setVisible(true);


} catch (IOException ioe) {} catch (MediaException me) {}
}


private void RecordVideo()
{
try{
control = (RecordControl)player.getControl("RecordControl");
control.setRecordLocation(URL);// eg: http://abc.com/..
player.start();
repaint();
control.startRecord();
}
catch (Exception e)
{
Alert alert = new Alert("Error
Record",e.getMessage),null,AlertType.ERROR);
Display.getDisplay(mid).setCurrent(alert);
}
}


private void StopVideoRecording()
{
try{
control.stopRecord();
control.commit();
player.stop();
player.deallocate();
player.close();

repaint();
}
catch (Exception e)
{
Alert alert = new Alert("Stop",e+"",null,AlertType.ERROR);
Display.getDisplay(mid).setCurrent(alert);
}
}

pls check and reply

thanks,
jitu_goldie..

hi jitu
i think that the network operation to send the data directly may create a bottleneck in the recording as the camera will generate the data very fastly and the network will not be able to send it that fast and hence may slow down the entire process

This is my doubt plz clarify it
regards
Arun Gupta

[jitu_goldie]

Hi,

hi jitu
i think that the network operation to send the data directly may create a bottleneck in the recording as the camera will generate the data very fastly and the network will not be able to send it that fast and hence may slow down the entire process

This is my doubt plz clarify it
regards
Arun Gupta

have u read out the functionality of setRecordLocation(String URL). Pls check and confirm.

[shashankgr8]

can you tell me the procedure of recording more than 5 sec of video ... atleast i want to store the video for 5 min is their any way to record the video of that much time ...

i am using one concept that i m using two stream mean while one stream will record the video one stream will save it to file and vice versa..


Do you have any idea abt that.. any alternative method if u have then tell me plz

Thanks and Regards
Shashank Shekhar

[jitu_goldie]

Hi,
The code given in my previous post by me is well tested for 10 minutes of recording and is working well. You can use any one of the option from setRecordStream or setRecordLocation for this. Only after commiting the recordcontrol u can access the data. If u want to save the recorded file to file system then pls use setRecordstream else in case of server uploading can take any of the method discuss above. whatever u want to do u have to call commit function before uploading or saving file to device.

If still u have anymore confusion please discuss here.

thanks,
jitu_goldie..

[shashankgr8]

hi can i merge two 3gp video in j2me