Accessing 127.0.0.1 with the XmlHTTPRequest class

[mfabiop]

Hi All,

I'm developing a Widget that access services in a mobile web server, just like this article (http://wiki.forum.nokia.com/index.ph...te_using_PyS60).

My problem is...

When i call a xmlhttp.open("GET","http://127.0.0.1:5004/get_speed",true), with "xmlhttp" of the XmlHTTPRequest type, the device (N95 8GB) open the "access points" list and i must chose one to connect it. If i don't chose one, the xmlhttp.open method doesn't work.

But i'm accessing a local mobile web server. The mobile web server was started previously in the device.

Anyone know what i can do to the WRT doesn't try to connect an access point and connect the local web server directly?

Thanks.

[geri-m]

Hi, as soon as you enter a URL/IP-Address in the open() Methode, this window pops up; have you tried "localhost" instead? Or have you tried just reading a file? just some ideas.

Cheers, geri-m

[mfabiop]

Hi geri-m,

Thanks for reply! I have tried "localhost" but it doesn't work too.

I didn't try a local xml file, but i have to access my mobile web server because it access a bluetooth device for my widget.

But i'll try a local xml file and post the result here.

Thanks!

[mfabiop]

I got my N96 last week and did a test. The problem doesn't happen in N96.

Thx

[weileylee]

Hi, as soon as you enter a URL/IP-Address in the open() Methode, this window pops up; have you tried "localhost" instead? Or have you tried just reading a file? just some ideas.

As far as I know, "localhost" is not working on Symbian system. You can check this link:

http://wiki.opensource.nokia.com/pro...ages#Localhost

I was actually doing tha same thing as you did, but I didn't have this problem at all. The only difference in my code is that I wasn't specify the port number. I was just using the default port 80. So maybe you should try using the default http port to see if that works.