unicode char comparison

[foosion]

I'd like to compare a user input char to a unicode char. My code is failing. How to fix? For example:

from appuifw import *
p = query(u'enter', 'text')  # user inputs £ using the chr key on the phone
if p == u'£' or p == '£':
    note(u'match')

Does not result in a match. How do I do the comparison so that it works?

PyS60 1.9.7

[gaba88]

I'd like to compare a user input char to a unicode char. My code is failing. How to fix? For example:

from appuifw import *
p = query(u'enter', 'text')  # user inputs £ using the chr key on the phone
if p == u'£' or p == '£':
    note(u'match')

Does not result in a match. How do I do the comparison so that it works?

PyS60 1.9.7

hello foosion

can you tell me what sort of error you are getting, the script above seems perfect.

Regards,

[foosion]

I'm not getting any errors, it's just that the program does not recognize the input pound char as equal to the pound char in the program.

I suspect it's for reasons similar to those covered in this: http://stackoverflow.com/questions/4...ings-in-python but I can't figure out how to get it to work in PyS60

[simo.salminen]

Try this.

if char == u"\u00a3": # Unicode Character 'POUND SIGN' (U+00A3)
print "match"




Or, configure your editor to use utf-8, and use corresponding encoding header at the start of the python file. Then write normally using string literals. (u"€" etc). More info: http://www.amk.ca/python/howto/unicode and http://www.joelonsoftware.com/articles/Unicode.html

[foosion]

from appuifw import *
p = query(u'enter', 'text')  # user inputs £ or € using the chr key on the phone
if p == u'\u00a3':
    note(u'pound')
elif p == u'\u20ac':
    note(u'euro')
else:
    note(u'neither')

actually works

thanks