Error- first argument must be callable

[arnab321]

my code fragment:

		def receive(self):
		c=0
		prev=""
		f= file(self.scr, "wb+")
		while 1==1: #r != "\n" and r != "\r":
			r = self.rep.read(1)
			if r=="\n":
				if prev == "\n":
					c=c+1
			prev=r
			if c==8:
				c=0
				break
			f.write(r)
			f.flush()

d = App()
d.run()
thread.start_new_thread(d.receive(), ())   
d.close()

the app runs fine initially, but the thread is executed only once, and when the thread is completed, the app crashes with " thread.start_new_thread(d.receive(), ()) - first argument must be callable"

[bogdan.galiceanu]

It seems you are actually calling the method instead of just specifying it. Try:

thread.start_new_thread(d.receive, ())