Opening a ContextMenu placed in another file

[pavneetarora]

I am trying to isolate ContextMenus, which are somewhat generic, i.e., have Edit+Delete options into a standalone QML file.

Simple question: how does one invoke the open() method from the Qt Component reference. The following code is wrong, but you can get a sense of what I am trying to do:

        onPressAndHold: ProjectContextMenu {}.open()

I had also tried the basic:

        onPressAndHold: ProjectContextMenu {}

but this results in the error:

Cannot assign object type ContextMenu_QMLTYPE_57 with no default method

advTHANKSance

[kunal_the_one]

To me it looks like you are creating QML Context menu component and trying to open it. I dont think this way QML works. I suggest you to create context menu element in your current QML and use id to open it. like

MouseArea {
id: longPressArea
anchors.fill: parent
onPressAndHold: myContextMenu.open()
}
}

check this link here

http://harmattan-dev.nokia.com/docs/...ntextmenu.html

[pavneetarora]

You are quite correct. I am trying to isolate common elements much as one would do by declaring other Qt Components in external files. But I gather that QML isn't designed to do this for every component.

Are there specific `types' of components where it make sense to put into another file, e.g., visual only?

Thanks.

[chanderk]

I remember doing something like

ExternalContextmenu{
id: externalmenu
}

on some,
onClicked: {
externalmenu.open()
}

ExternalContextmenu.qml will contain the actual ContextMenu representation..

-CK

[pavneetarora]

But I thought that id is not visible outside of the local file, so wouldn't the externalmenu.open() invocation would fail as a consequence?

[chanderk]

As,

ExternalContextmenu{
id: externalmenu
}

is going to be in ur local qml file, its gonna be the local instance.. isnt it ?

-CK