How to move on to the next page in Qml?

[mkhpad]

Hi all,
I am working on an application where i am in need of help:

I am having a button in the main page.qml(main window) and when i click on it,it must go to the next page(.qml) where i have a webview as such:

ABC.qml:

import QtWebKit 1.0

WebView {
url: "http://www.google.co.in"
preferredWidth: 490
preferredHeight: 400
scale: 0.5
smooth: false
}

and in the click event i am having:

main.qml:

onJobsClicked: {
if (currentPage != "jobs")
MCWHandler.pushPage("jobs")

currentPage = "jobs"
header.headerText = "Jobs"
busyVisible = true
Qt.resolvedUrl ("ABC.qml")
stateIndexProperty = 2
tab.visible = false
showStandardListView()
}

From my code i was not able to move on to next page.
Can anyone help me with this ??

Regards,
Harish.M

[gaba88]

Hello Harish,

the best way to do that is to QQC PageStack Component please try that.

[mkhpad]

Thanks for your reply gaba...

I don't want to use Page Stack Component as because i am in need to open a web browser inside my application and not externally....

If i use Page Stack Component:I need to design a Page with all the requirements that was in my application already so now i had changed my code as such:

main.qml:

onGoogleClicked: {
if (currentPage != "google")
MCWHandler.pushPage("google")

currentPage = "google"
header.headerText = "Google"
busyVisible = true
ABC.google()
stateIndexProperty = 2
tab.visible = false
showStandardListView()
}

and in ABC.cpp:

bool ABC::google()
{
QWebView *view = new QWebView();
view->load(QUrl("http://www.google.co.in"));
view->show();

}

This is the code i am currently using and in this also the URL opens externally and not inside my application....

I need to open the web browser inside my application so that all the qml part remain as such when this URL loads...
So can you or anyone else help me with this and provide me a solution?

[kkrish]

try webview element. You will find lots of example on wiki and qt sdk.

[mkhpad]

Hi Kkrish these are the two ways i have tried:

main.qml:

onJobsClicked: {
if (currentPage != "jobs")
ABC.pushPage("jobs")

currentPage = "jobs"
header.headerText = "Jobs"
busyVisible = true
jobsPage.visible = true
stateIndexProperty = 2
showStandardListView()
}



function showStandardListView()
{
turnVisibleOff()
standardListView.visible = true
}

JobsPage {
id: jobsPage
visible: false
anchors.top: header.bottom
width: screenWidth
anchors.bottom: parent.bottom
}

JobsPage.qml:

import QtQuick 1.0
import com.nokia.symbian 1.1
import QtWebKit 1.0

Page {
id: ab

x: 0
y: 0
width: 360
height: 640


WebView {
x: 0
y: 0
url: "http://www.naukri.com"
width: 360
height: 640
anchors.rightMargin: 0
anchors.topMargin: 166
opacity: 1
smooth: false

}


}

From this code i was able to open the browser with the URL i had given but when i click on the back button it does not works..


Second try is the one i had explained in the #3

Anyone come with the solution ?