Getting X from flickable elements

[CLTSchwarz]

I posted this in the QT Beginner section but I'm getting no answers so I'm posting here.

I have a Page that contains a Flickable element and in that element I have an Image and I allow left to right flicking only flickableDirection : Flickable.HorizontalFlick
I use onFlickEnded: to set a text field to image1.x but it only ever returns the initial x location of the image, but I expect it to be the new x location of the image which is somewhere off of the screen after a flick is ended!

Here is the code:

Page {
    id: mainPage
    Flickable {
        id: flickable1
        x: 0
        contentWidth: image1.width;   //It's a wide image, much wider than the screen
        onFlickEnded:   debugging.text = image1.x
        Image {
            id: image1
            fillMode: Image.PreserveAspectFit
            source: "Slide.jpg"
            sourceSize.width: 2000
            x: 10

Whenever the image is flicked onFlickEnded sets debugging.text to 10 (the initial x value for the image). How do I work out which portion of the image is on the screen? How do I get the new x value?
Note: above I left out a few irrelevant lines of code like the y-value etc. but I can post the full code if anyone wants. My target platform is Symbian.


Thanks.

[kusumk]

Yes the debugging.text will always hold 10 as the x property of the image actually never changes.

AFAIU, you can fetch the new x value for the visible area on the flickable element.
Please try -
onFlickEnded : flickable1.visibleArea.xPosition + 10 // + 10 so that it gives for the xpoistion on image instead of the entire flickable..

(no idea if we can get it for the image directly hence the above workaround)

[CLTSchwarz]

Thankyou very much!
So to understand this, I declared a static x property rather than initialising a dynamic x value? That makes sense but just checking that I have it right.
I'll try using the visible area property.